Indiana State Indicators
Graphing
Calculators are recommended!
This assessment covers the following state indicators: A1.4.1,
A1.4.6, A2.1.2, A2.1.4, A2.2.3, A2.3.1, A2.3.3, and A2.3.5.
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Solve the linear system.
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1
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A | (–1, 3) | B | (1, –3) | C | (3, –1) | D | (–3,
1) |
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Write the number in the form a +
bi.
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2
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Graph the inequality.
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3
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4
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Let  and  . Find  and its domain.
A |  ; all real numbers | B |  ; all
real numbers | C |  ; all real numbers except x =  | D |  ; all real numbers except
x =  |
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5
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Graph the equation  by finding the
intercepts.
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6
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Use the slope and y-intercept to graph the equation.
y =
 x + 3
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Write the linear inequality shown in the
graph.
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7
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Simplify the expression.
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8
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9
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Solve the equation using the zero-product property.
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10
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A | n =  or n =  | C | n = 0 or
n =  | B | n =  or n =
 | D | n = 0 or
n =  |
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Use the quadratic formula to solve the equation.
If necessary, round to the nearest hundredth.
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11
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A | –14, 11.33 | B | –5.57, 0.24 | C | –0.12, 2.79 | D | –2.79,
0.12 |
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12
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Find  .
A |  | B |  | C | –7 | D | 7 |
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13
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What is the solution of the system of equations?
y = x +
7
y = –x – 3
A | (2, –5) | B | (–5, 2) | C | (2, –5) | D | (0,
7) |
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14
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Suppose you have 58 feet of fencing to enclose a
rectangular dog pen. The function  , where x = width, gives you the area of the
dog pen in square feet. What width gives you the maximum area? What is the maximum area? Round to the
nearest tenth as necessary.
A | width = 14.5 ft; area = 210.3 ft2 | C | width = 29 ft; area = 449.5
ft2 | B | width = 14.5 ft; area = 630.8 ft2 | D | width = 29 ft; area = 210.3
ft2 |
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Solve the equation by
factoring.
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15
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A | z = 9 or z = –4 | C | z = 9 or z =
4 | B | z = –9 or z = 4 | D | z = –9 or z =
–4 |
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16
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The length of a rectangle is 9 cm more than four times the width. If the
perimeter of the rectangle is 78 cm, what are its dimensions?
A | length = 33 cm; width = 15 cm | C | length = 6 cm; width = 33
cm | B | length = 33 cm; width = 6 cm | D | length = 15 cm; width = 15 cm |
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17
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Identify the vertex and the y-intercept
of the graph of the function  .
A | vertex: (–2, –5);
y-intercept: –1 | C | vertex: (–2,
5);
y-intercept: –1 | B | vertex: (2, –5);
y-intercept:
–1 | D | vertex: (2,
5);
y-intercept: 4 |
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Write a function rule for the
table.
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18
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19
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Evaluate  for x =
–2.
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Graph the equation.
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20
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y = –2
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